What is \sqrt[8]{(x^2-4x)^5} ?

The solution to \sqrt[8]{(x^2-4x)^5} is (x^2-4x)^{5/8}

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simplify \sqrt[8]{(x^2-4x)^5}

simplify

(x^{2} - 4 x)^{\frac{5}{8}}

Solution steps

Apply radical rule:

= ((x^{2} - 4 x)^{5})^{\frac{1}{8}}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= (x^{2} - 4 x)^{5 \cdot \frac{1}{8}}

5 \cdot \frac{1}{8} = \frac{5}{8}

= (x^{2} - 4 x)^{\frac{5}{8}}

(5 a) (2 a) (a^{3} - 3 a^{2} + a)

\frac{x + 4}{x - 1}

91.2 (1 - \frac{1}{4})^{- 1}

\frac{x + 2}{x + 3}

What is \sqrt[8]{(x^2-4x)^5} ?
The solution to \sqrt[8]{(x^2-4x)^5} is (x^2-4x)^{5/8}