What is e^{-7t}((s-3)/(s^2+4s-3)) ?

The solution to e^{-7t}((s-3)/(s^2+4s-3)) is (s-3)/(e^{7t)(s^2+4s-3)}

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simplify e^{-7t}((s-3)/(s^2+4s-3))

simplify

e^{- 7 t} (\frac{s - 3}{s ^{2} + 4 s - 3})

\frac{s - 3}{e ^{7 t} ( s ^{2} + 4 s - 3 )}

Solution steps

e^{- 7 t} (\frac{s - 3}{s ^{2} + 4 s - 3})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{7 t}} \cdot \frac{s - 3}{s ^{2} + 4 s - 3}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot ( s - 3 )}{e ^{7 t} ( s ^{2} + 4 s - 3 )}

1 \cdot (s - 3) = s - 3

= \frac{s - 3}{e ^{7 t} ( s ^{2} + 4 s - 3 )}

(3 p^{4} q) (12 p^{3} q^{2})

e^{- 4 \cdot 0}

(e^{3})^{x}

(\frac{2 ^{3}}{3})^{5} \cdot (\frac{3 ^{2}}{2 ^{5}})^{- 2}

What is e^{-7t}((s-3)/(s^2+4s-3)) ?
The solution to e^{-7t}((s-3)/(s^2+4s-3)) is (s-3)/(e^{7t)(s^2+4s-3)}