What are the solutions to the equation x^2+11x+28=0 ?

The solutions to the equation x^2+11x+28=0 are x=-4,x=-7

Find the zeros of x^2+11x+28=0

The zeros of x^2+11x+28=0 are x=-4,x=-7

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x^{2} + 11 x + 28 = 0

x = - 4, x = - 7

Solution steps

x^{2} + 11 x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 28}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 28 = 3

x_{1, 2} = \frac{- 11 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 3}{2 \cdot 1}, x_{2} = \frac{- 11 - 3}{2 \cdot 1}

x = \frac{- 11 + 3}{2 \cdot 1} : - 4

x = \frac{- 11 - 3}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = - 4, x = - 7

2 v^{2} + 9 v + 4

\frac{1}{8} (- \frac{4}{7})

e^{9} = y

m^{2} - \frac{2}{3} m = \frac{1}{3}

- 25 t^{2} + 200 t + 375 = 0

What are the solutions to the equation x^2+11x+28=0 ?
The solutions to the equation x^2+11x+28=0 are x=-4,x=-7
Find the zeros of x^2+11x+28=0
The zeros of x^2+11x+28=0 are x=-4,x=-7