What is simplify-log_{10}(2)E^{-8} ?

The solution to simplify-log_{10}(2)E^{-8} is -(log_{10}(2))/(E^8)

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simplify-log_{10}(2)E^{-8}

simplify

- lo g_{10} (2) E^{- 8}

- \frac{lo g _{10} ( 2 )}{E ^{8}}

Solution steps

- lo g_{10} (2) E^{- 8}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

E^{- 8} = \frac{1}{E ^{8}}

= - lo g_{10} (2) \frac{1}{E ^{8}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{lo g _{10} ( 2 ) \cdot 1}{E ^{8}}

Apply rule:

a \cdot 1 = a

lo g_{10} (2) \cdot 1 = lo g_{10} (2)

= - \frac{lo g _{10} ( 2 )}{E ^{8}}

1 e^{- 8}

(x + 1)^{2} (x - 1) (x - 2)^{2}

1 e^{- 3}

1 e^{- 4}

What is simplify-log_{10}(2)E^{-8} ?
The solution to simplify-log_{10}(2)E^{-8} is -(log_{10}(2))/(E^8)