What is (2.35-1)(8.8542*10^{-12})(8*10^3) ?

The solution to (2.35-1)(8.8542*10^{-12})(8*10^3) is (1195317)/(1.25E13)

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simplify (2.35-1)(8.854210^{-12})(810^3)

simplify

(2.35 - 1) (8.8542 \cdot 1 0^{- 12}) (8 \cdot 1 0^{3})

\frac{1195317}{1.25 E 13}

Decimal Notation

9.56254 E - 8

Solution steps

(2.35 - 1) (8.8542 \cdot 1 0^{- 12}) (8 \cdot 1 0^{3})

Subtract the numbers:

2.35 - 1 = 1.35

= 1.35 \cdot 8.8542 \cdot 1 0^{- 12} \cdot 8 \cdot 1 0^{3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 12} = \frac{1}{1 0 ^{12}}

= 1.35 \cdot 8.8542 \cdot \frac{1}{1 0 ^{12}} \cdot 8 \cdot 1 0^{3}

1 0^{3} = 1000

= 1.35 \cdot 8.8542 \cdot \frac{1}{1 0 ^{12}} \cdot 8 \cdot 1000

Multiply the numbers:

1.35 \cdot 8.8542 \cdot 8 \cdot 1000 = 95625.36

= 95625.36 \cdot \frac{1}{1 0 ^{12}}

95625.36 \cdot \frac{1}{1 0 ^{12}} = \frac{95625.36}{1 0 ^{12}}

= \frac{95625.36}{1 0 ^{12}}

\frac{95625.36}{1 0 ^{12}} = \frac{9562536}{100 \cdot 1 0 ^{12}}

= \frac{9562536}{100 \cdot 1 0 ^{12}}

Factor the number:

9562536 = 4 \cdot 2390634

= \frac{4 \cdot 2390634}{100 \cdot 1 0 ^{12}}

Factor the number:

100 = 4 \cdot 25

= \frac{4 \cdot 2390634}{4 \cdot 25 \cdot 1 0 ^{12}}

Cancel the common factor:

4

= \frac{2390634}{25 \cdot 1 0 ^{12}}

Factor the number:

2390634 = 2 \cdot 1195317

= \frac{2 \cdot 1195317}{25 \cdot 1 0 ^{12}}

Factor

1 0^{12} : 2^{12} \cdot 5^{12}

= \frac{2 \cdot 1195317}{25 \cdot 2 ^{12} \cdot 5 ^{12}}

\frac{2}{2 ^{12}} = \frac{1}{2 ^{11}}

= \frac{1195317}{25 \cdot 2 ^{11} \cdot 5 ^{12}}

25 \cdot 2^{11} \cdot 5^{12} = 1.25 E 13

= \frac{1195317}{1.25 E 13}

8.854 \times 1 0^{- 12} \times \frac{0.1}{0.0005}

f (x) = arccot (sin (x)) x

\frac{5 + x + 9}{3 - x}

e^{3 t} \cdot (- 2) e^{- 2 t}

x^{7 x}

What is (2.35-1)(8.8542*10^{-12})(8*10^3) ?
The solution to (2.35-1)(8.8542*10^{-12})(8*10^3) is (1195317)/(1.25E13)