What are the solutions to the equation -16t^2+64t+80=0 ?

The solutions to the equation -16t^2+64t+80=0 are t=-1,t=5

Find the zeros of -16t^2+64t+80=0

The zeros of -16t^2+64t+80=0 are t=-1,t=5

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- 16 t^{2} + 64 t + 80 = 0

t = - 1, t = 5

Solution steps

- 16 t^{2} + 64 t + 80 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 64 \pm 6 4 ^{2} - 4 ( - 16 ) \cdot 80}{2 ( - 16 )}

6 4^{2} - 4 (- 16) \cdot 80 = 96

t_{1, 2} = \frac{- 64 \pm 96}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 64 + 96}{2 ( - 16 )}, t_{2} = \frac{- 64 - 96}{2 ( - 16 )}

t = \frac{- 64 + 96}{2 ( - 16 )} : - 1

t = \frac{- 64 - 96}{2 ( - 16 )} : 5

The solutions to the quadratic equation are:

t = - 1, t = 5

4^{2} \cdot 4^{4}

r^{3} - \frac{7}{9} r - \frac{2}{9}

∣ 5 x - 7 ∣ < 13

- 319 = 11 n

\frac{3}{4} = \frac{1}{2} + \frac{d}{9}

What are the solutions to the equation -16t^2+64t+80=0 ?
The solutions to the equation -16t^2+64t+80=0 are t=-1,t=5
Find the zeros of -16t^2+64t+80=0
The zeros of -16t^2+64t+80=0 are t=-1,t=5