What is (e^xcos(e^x)-sin(e^x))(e^{-2x}) ?

The solution to (e^xcos(e^x)-sin(e^x))(e^{-2x}) is (e^xcos(e^x)-sin(e^x))/(e^{2x)}

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simplify (e^xcos(e^x)-sin(e^x))(e^{-2x})

simplify

(e^{x} cos (e^{x}) - sin (e^{x})) (e^{- 2 x})

\frac{e ^{x} cos ( e ^{x} ) - sin ( e ^{x} )}{e ^{2 x}}

Solution steps

(e^{x} cos (e^{x}) - sin (e^{x})) (e^{- 2 x})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{2 x}} (e^{x} cos (e^{x}) - sin (e^{x}))

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( e ^{x} cos ( e ^{x} ) - sin ( e ^{x} ) )}{e ^{2 x}}

1 \cdot (e^{x} cos (e^{x}) - sin (e^{x})) = e^{x} cos (e^{x}) - sin (e^{x})

= \frac{e ^{x} cos ( e ^{x} ) - sin ( e ^{x} )}{e ^{2 x}}

10^{\frac{3}{4}}

4 (3 \cdot e^{- x^{4}}) \cdot x^{3}

6000 (1 + \frac{0.67}{360})^{- 1440}

20 (60) e^{- 0.06 (60)}

What is (e^xcos(e^x)-sin(e^x))(e^{-2x}) ?
The solution to (e^xcos(e^x)-sin(e^x))(e^{-2x}) is (e^xcos(e^x)-sin(e^x))/(e^{2x)}