What are the solutions to the equation (x+3)(x-4)=0 ?

The solutions to the equation (x+3)(x-4)=0 are x=-3,x=4

Find the zeros of (x+3)(x-4)=0

The zeros of (x+3)(x-4)=0 are x=-3,x=4

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(x + 3) (x - 4) = 0

x = - 3, x = 4

Solution steps

(x + 3) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x - 4 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 4 = 0 : x = 4

The solutions to the quadratic equation are:

x = - 3, x = 4

- 4 ∣ s - 20 ∣ < - 16

a^{2} + 3^{2} = 7^{2}

2 v^{2} - 33 v + 16

π - \frac{2 π}{3}

\frac{x ^{2} ( 3 - x )}{x + 2} \leq 0

What are the solutions to the equation (x+3)(x-4)=0 ?
The solutions to the equation (x+3)(x-4)=0 are x=-3,x=4
Find the zeros of (x+3)(x-4)=0
The zeros of (x+3)(x-4)=0 are x=-3,x=4