What is sqrt(2x-1)*(2x-1)^{-1} ?

The solution to sqrt(2x-1)*(2x-1)^{-1} is 1/(sqrt(2x-1))

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simplify sqrt(2x-1)*(2x-1)^{-1}

simplify

2 x - 1 \cdot (2 x - 1)^{- 1}

\frac{1}{2 x - 1}

Solution steps

2 x - 1 (2 x - 1)^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(2 x - 1)^{- 1} = \frac{1}{2 x - 1}

= 2 x - 1 \frac{1}{2 x - 1}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 x - 1 \cdot 1}{2 x - 1}

Apply rule:

a \cdot 1 = a

2 x - 1 \cdot 1 = 2 x - 1

= \frac{2 x - 1}{2 x - 1}

Apply radical rule:

a = a a

2 x - 1 = 2 x - 1 2 x - 1

= \frac{2 x - 1}{2 x - 1 2 x - 1}

Cancel the common factor:

2 x - 1

= \frac{1}{2 x - 1}

(3.3) (885 \cdot 1 0^{- 12}) (0.04)

43000 (1.01)^{- 5}

(4 x^{5}) 4

9.61128 \cdot e^{- \frac{68 \cdot 9.61128}{2 \cdot 0.26}}

What is sqrt(2x-1)*(2x-1)^{-1} ?
The solution to sqrt(2x-1)*(2x-1)^{-1} is 1/(sqrt(2x-1))