What is (9*10^{-9})(3*10^{-6})(4*10^{-6}) ?

The solution to (9*10^{-9})(3*10^{-6})(4*10^{-6}) is (27)/(250000000*1000000^2)

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simplify (910^{-9})(310^{-6})(4*10^{-6})

simplify

(9 \cdot 1 0^{- 9}) (3 \cdot 1 0^{- 6}) (4 \cdot 1 0^{- 6})

\frac{27}{250000000 \cdot 100000 0 ^{2}}

Decimal Notation

1.08 E - 19

Solution steps

(9 \cdot 1 0^{- 9}) (3 \cdot 1 0^{- 6}) (4 \cdot 1 0^{- 6})

Simplify

9 \cdot 1 0^{- 9} : \frac{9}{1000000000}

= \frac{9}{1000000000} \cdot 3 \cdot 1 0^{- 6} \cdot 4 \cdot 1 0^{- 6}

1 0^{- 6} = \frac{1}{1000000}

= \frac{9}{1000000000} \cdot 3 \cdot \frac{1}{1000000} \cdot 4 \cdot 1 0^{- 6}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 6} = \frac{1}{1 0 ^{6}}

= \frac{9}{1000000000} \cdot 3 \cdot \frac{1}{1000000} \cdot 4 \cdot \frac{1}{1 0 ^{6}}

1 0^{6} = 1000000

= \frac{9}{1000000000} \cdot 3 \cdot \frac{1}{1000000} \cdot 4 \cdot \frac{1}{1000000}

Multiply the numbers:

3 \cdot 4 = 12

= \frac{9}{1000000000} \cdot 12 \cdot \frac{1}{1000000} \cdot \frac{1}{1000000}

Apply exponent rule:

aa = a^{2}

\frac{1}{1000000} \cdot \frac{1}{1000000} = (\frac{1}{1000000})^{2}

= \frac{9}{1000000000} \cdot 12 (\frac{1}{1000000})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

(\frac{1}{1000000})^{2} = \frac{1 ^{2}}{100000 0 ^{2}}

= \frac{9}{1000000000} \cdot 12 \cdot \frac{1 ^{2}}{100000 0 ^{2}}

1^{2} = 1

= \frac{9}{1000000000} \cdot 12 \cdot \frac{1}{100000 0 ^{2}}

\frac{9}{1000000000} \cdot 12 \cdot \frac{1}{100000 0 ^{2}} = \frac{27}{250000000 \cdot 100000 0 ^{2}}

= \frac{27}{250000000 \cdot 100000 0 ^{2}}

e^{(- 365 \cdot \frac{2}{600})} \frac{( 365 \cdot \frac{2}{600} ) ^{3}}{3 !}

\frac{2 x + 1}{2 x}

\frac{2 s - 3}{( s + 3 ) ^{s}} e^{- 8 s}

x e^{x}

What is (9*10^{-9})(3*10^{-6})(4*10^{-6}) ?
The solution to (9*10^{-9})(3*10^{-6})(4*10^{-6}) is (27)/(250000000*1000000^2)