What is \det(8B)A^2B^{-2}A^T ?

The solution to \det(8B)A^2B^{-2}A^T is (A^{T+2}\det(8B))/(B^2)

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simplify \det(8B)A^2B^{-2}A^T

simplify

det (8 B) A^{2} B^{- 2} A^{T}

\frac{A ^{T + 2} det ( 8 B )}{B ^{2}}

Solution steps

det (8 B) A^{2} B^{- 2} A^{T}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

A^{2} A^{T} = A^{2 + T}

= det (8 B) B^{- 2} A^{2 + T}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

B^{- 2} = \frac{1}{B ^{2}}

= \frac{1}{B ^{2}} A^{T + 2} det (8 B)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot det ( 8 B ) A ^{2 + T}}{B ^{2}}

Multiply:

1 \cdot det (8 B) = det (8 B)

= \frac{A ^{T + 2} det ( 8 B )}{B ^{2}}

(5 x^{3}) (4 x)

4096

(u - v)^{2} (u + v)^{2}

\frac{- 9}{3}

(\frac{2}{3})^{2} l e f t (\frac{2}{3})^{2}

What is \det(8B)A^2B^{-2}A^T ?
The solution to \det(8B)A^2B^{-2}A^T is (A^{T+2}\det(8B))/(B^2)