What is expan(4-(4-1/16 x^2))(4-(4-1/16 x^2)) ?

The solution to expan(4-(4-1/16 x^2))(4-(4-1/16 x^2)) is (enx^5pa)/(256)

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simplify expan(4-(4-1/16 x^2))(4-(4-1/16 x^2))

simplify

e x p an (4 - (4 - \frac{1}{16} x^{2})) (4 - (4 - \frac{1}{16} x^{2}))

\frac{e n x ^{5} p a}{256}

Solution steps

e x p an (4 - (4 - \frac{1}{16} x^{2})) (4 - (4 - \frac{1}{16} x^{2}))

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

(4 - (4 - \frac{1}{16} x^{2})) (4 - (4 - \frac{1}{16} x^{2})) = (4 - (- \frac{1}{16} x^{2} + 4))^{1 + 1}

= e x p an (4 - (4 - \frac{1}{16} x^{2}))^{1 + 1}

Add the numbers:

1 + 1 = 2

= e x p an (4 - (4 - \frac{1}{16} x^{2}))^{2}

(4 - (4 - \frac{1}{16} x^{2}))^{2} = \frac{x ^{4}}{1 6 ^{2}}

= e n \frac{x ^{4}}{1 6 ^{2}} x p a

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{x ^{4} e x p an}{1 6 ^{2}}

x^{4} e x p an = e n x^{5} p a

= \frac{e n x ^{5} p a}{1 6 ^{2}}

1 6^{2} = 256

= \frac{e n x ^{5} p a}{256}

q a^{p}

x^{^{''}}

3.24078 \cdot 1 0^{- 20} \cdot 70

\frac{x ^{2}}{sin ^{2} ( x )}

(4 \cdot 1 0^{- 7}) (0.62)

What is expan(4-(4-1/16 x^2))(4-(4-1/16 x^2)) ?
The solution to expan(4-(4-1/16 x^2))(4-(4-1/16 x^2)) is (enx^5pa)/(256)