What is simplify-2.18*10^{-18}(1/(5^2)-1/(4^2)) ?

The solution to simplify-2.18*10^{-18}(1/(5^2)-1/(4^2)) is (981)/(10^{18)*20000}

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simplify-2.18*10^{-18}(1/(5^2)-1/(4^2))

simplify

- 2.18 \cdot 1 0^{- 18} (\frac{1}{5 ^{2}} - \frac{1}{4 ^{2}})

\frac{981}{1 0 ^{18} \cdot 20000}

Decimal Notation

4.905 E - 20

Solution steps

- 2.18 \cdot 1 0^{- 18} (\frac{1}{5 ^{2}} - \frac{1}{4 ^{2}})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 18} = \frac{1}{1 0 ^{18}}

= - 2.18 \cdot \frac{1}{1 0 ^{18}} (\frac{1}{5 ^{2}} - \frac{1}{4 ^{2}})

\frac{1}{5 ^{2}} - \frac{1}{4 ^{2}} = - \frac{9}{400}

= - 2.18 \cdot \frac{1}{1 0 ^{18}} (- \frac{9}{400})

Apply rule:

- a (- b) = ab

- 2.18 \cdot \frac{1}{1 0 ^{18}} (- \frac{9}{400}) = 2.18 \cdot \frac{1}{1 0 ^{18}} \cdot \frac{9}{400}

= 2.18 \cdot \frac{1}{1 0 ^{18}} \cdot \frac{9}{400}

2.18 = \frac{109}{50}

= \frac{109}{50} \cdot \frac{1}{1 0 ^{18}} \cdot \frac{9}{400}

\frac{109}{50} \cdot \frac{1}{1 0 ^{18}} \cdot \frac{9}{400} = \frac{981}{1 0 ^{18} \cdot 20000}

= \frac{981}{1 0 ^{18} \cdot 20000}

5 x^{3} e^{- x}

- 12000 (\frac{1 - ( 1 + 0.0125 )}{0.0125})^{- 60}

3 π

\frac{π}{180} \cdot (1 0^{13})^{2} \cdot (180 - 36)

What is simplify-2.18*10^{-18}(1/(5^2)-1/(4^2)) ?
The solution to simplify-2.18*10^{-18}(1/(5^2)-1/(4^2)) is (981)/(10^{18)*20000}