What are the solutions to the equation x^2+60=-16x ?

The solutions to the equation x^2+60=-16x are x=-6,x=-10

Find the zeros of x^2+60=-16x

The zeros of x^2+60=-16x are x=-6,x=-10

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x^{2} + 60 = - 16 x

x = - 6, x = - 10

Solution steps

x^{2} + 60 = - 16 x

Move

16 x

to the left side

x^{2} + 60 + 16 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 16 x + 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 60}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 60 = 4

x_{1, 2} = \frac{- 16 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 4}{2 \cdot 1}, x_{2} = \frac{- 16 - 4}{2 \cdot 1}

x = \frac{- 16 + 4}{2 \cdot 1} : - 6

x = \frac{- 16 - 4}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 6, x = - 10

0 = x^{2} + 6 x + 4

7 w - 3 (4 w + 8) = 11

8 x^{- 2}

\frac{3}{4} x - 2 x \leq 1 + 2

4 {x - (3 x - 2)} > 3 (x + 5) - 15

What are the solutions to the equation x^2+60=-16x ?
The solutions to the equation x^2+60=-16x are x=-6,x=-10
Find the zeros of x^2+60=-16x
The zeros of x^2+60=-16x are x=-6,x=-10