What is \sqrt[4]{((a^2+b^2)^2-(a^2-b^2)^2)^2} ?

The solution to \sqrt[4]{((a^2+b^2)^2-(a^2-b^2)^2)^2} is 2ab

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify \sqrt[4]{((a^2+b^2)^2-(a^2-b^2)^2)^2}

simplify

2 ab

Solution steps

Simplify

((a^{2} + b^{2})^{2} - (a^{2} - b^{2})^{2})^{2} : 16 a^{4} b^{4}

Apply radical rule:

assuming

a \geq 0

Apply radical rule:

assuming

a \geq 0

= 2 ab

e^{- 6 l n (y)}

e^{- 2 \cdot 1.7}

(2 \cdot 1 0^{- 4}) (8.1 \cdot 1 0^{- 1})

(2 b) (2 c) (2 b^{2}) (2 c^{2})

What is \sqrt[4]{((a^2+b^2)^2-(a^2-b^2)^2)^2} ?
The solution to \sqrt[4]{((a^2+b^2)^2-(a^2-b^2)^2)^2} is 2ab