What are the solutions to the equation 8x^2+21=-59x ?

The solutions to the equation 8x^2+21=-59x are x=-3/8 ,x=-7

Find the zeros of 8x^2+21=-59x

The zeros of 8x^2+21=-59x are x=-3/8 ,x=-7

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8 x^{2} + 21 = - 59 x

x = - \frac{3}{8}, x = - 7

Decimal Notation

x = - 0.375, x = - 7

Solution steps

8 x^{2} + 21 = - 59 x

Move

59 x

to the left side

8 x^{2} + 21 + 59 x = 0

Write in the standard form

a x^{2} + b x + c = 0

8 x^{2} + 59 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 59 \pm 5 9 ^{2} - 4 \cdot 8 \cdot 21}{2 \cdot 8}

5 9^{2} - 4 \cdot 8 \cdot 21 = 53

x_{1, 2} = \frac{- 59 \pm 53}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 59 + 53}{2 \cdot 8}, x_{2} = \frac{- 59 - 53}{2 \cdot 8}

x = \frac{- 59 + 53}{2 \cdot 8} : - \frac{3}{8}

x = \frac{- 59 - 53}{2 \cdot 8} : - 7

The solutions to the quadratic equation are:

x = - \frac{3}{8}, x = - 7

- x^{2} - 5 x + 6 = 0

\frac{( - 2 ) ^{8} \cdot 5 ^{3}}{5 ^{4} \cdot 2 ^{10} \cdot 10}

(2 x^{\frac{1}{4}})^{4}

- 2 (y - 3) \leq 10

\frac{x ^{8}}{x ^{4}}

What are the solutions to the equation 8x^2+21=-59x ?
The solutions to the equation 8x^2+21=-59x are x=-3/8 ,x=-7
Find the zeros of 8x^2+21=-59x
The zeros of 8x^2+21=-59x are x=-3/8 ,x=-7