What is ((5!)/(3!(5-3)!))(x/3)^{5-3}(y^2)^3 ?

The solution to ((5!)/(3!(5-3)!))(x/3)^{5-3}(y^2)^3 is (10x^2y^6)/9

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simplify ((5!)/(3!(5-3)!))(x/3)^{5-3}(y^2)^3

simplify

(\frac{5 !}{3 ! ( 5 - 3 ) !}) (\frac{x}{3})^{5 - 3} (y^{2})^{3}

\frac{10 x ^{2} y ^{6}}{9}

Solution steps

(\frac{5 !}{3 ! ( 5 - 3 ) !}) (\frac{x}{3})^{5 - 3} (y^{2})^{3}

Apply rule:

(a) = a

(\frac{5 !}{3 ! ( 5 - 3 ) !}) = \frac{5 !}{3 ! ( 5 - 3 ) !}

= \frac{5 !}{3 ! ( 5 - 3 ) !} (\frac{x}{3})^{5 - 3} (y^{2})^{3}

Simplify

(\frac{x}{3})^{5 - 3} : \frac{x ^{2}}{9}

= \frac{5 !}{3 ! ( 5 - 3 ) !} \cdot \frac{x ^{2}}{9} (y^{2})^{3}

Simplify

(y^{2})^{3} : y^{6}

= \frac{5 !}{3 ! ( 5 - 3 ) !} \cdot \frac{x ^{2}}{9} y^{6}

Cancel

\frac{5 !}{3 ! ( 5 - 3 ) !} : 10

= 10 \cdot \frac{x ^{2}}{9} y^{6}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{10 x ^{2} y ^{6}}{9}

1.189 (0.22)^{- 0.097}

(2 x^{2})^{2}

\frac{t}{2} e^{- (\frac{( t - 2 )}{2})} u (\frac{t - 2}{2})

\frac{2}{7} \cdot \frac{2}{7}

15 n m n

What is ((5!)/(3!(5-3)!))(x/3)^{5-3}(y^2)^3 ?
The solution to ((5!)/(3!(5-3)!))(x/3)^{5-3}(y^2)^3 is (10x^2y^6)/9