What is (\sqrt[14]{2y})^{10} ?

The solution to (\sqrt[14]{2y})^{10} is 2^{5/7}y^{5/7}

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simplify (\sqrt[14]{2y})^{10}

simplify

2^{\frac{5}{7}} y^{\frac{5}{7}}

Solution steps

Apply radical rule:

= ((2 y)^{\frac{1}{14}})^{10}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= (2 y)^{\frac{1}{14} \cdot 10}

\frac{1}{14} \cdot 10 = \frac{5}{7}

= (2 y)^{\frac{5}{7}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= 2^{\frac{5}{7}} y^{\frac{5}{7}}

3 x^{4} (2 x)

(6.42 \cdot 1 0^{- 5}) \cdot (\frac{1000}{10 , 5})

3 \times 1 0^{- 9}

4 \cdot 1 0^{- 7} \cdot \frac{21}{0.5} \cdot 1000

\frac{7}{5} \cdot \frac{5}{5}

What is (\sqrt[14]{2y})^{10} ?
The solution to (\sqrt[14]{2y})^{10} is 2^{5/7}y^{5/7}