What is (2.5*10^{-5})*(1/2)*(293/305)^{1.75} ?

The solution to (2.5*10^{-5})*(1/2)*(293/305)^{1.75} is (293^{1.75})/(80000*305^{1.75)}

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simplify (2.510^{-5})(1/2)*(293/305)^{1.75}

simplify

(2.5 \cdot 1 0^{- 5}) \cdot (\frac{1}{2}) \cdot (\frac{293}{305})^{1.75}

\frac{29 3 ^{1.75}}{80000 \cdot 30 5 ^{1.75}}

Decimal Notation

0.00001 \dots

Solution steps

(2.5 \cdot 1 0^{- 5}) (\frac{1}{2}) (\frac{293}{305})^{1.75}

Apply rule:

(a) = a

(\frac{1}{2}) = \frac{1}{2}

= 2.5 \cdot 1 0^{- 5} \cdot \frac{1}{2} (\frac{293}{305})^{1.75}

1 0^{- 5} = \frac{1}{100000}

= 2.5 \cdot \frac{1}{100000} \cdot \frac{1}{2} (\frac{293}{305})^{1.75}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

(\frac{293}{305})^{1.75} = \frac{29 3 ^{1.75}}{30 5 ^{1.75}}

= 2.5 \cdot \frac{1}{100000} \cdot \frac{1}{2} \cdot \frac{29 3 ^{1.75}}{30 5 ^{1.75}}

2.5 = \frac{5}{2}

= \frac{5}{2} \cdot \frac{1}{100000} \cdot \frac{1}{2} \cdot \frac{29 3 ^{1.75}}{30 5 ^{1.75}}

\frac{5}{2} \cdot \frac{1}{100000} \cdot \frac{1}{2} \cdot \frac{29 3 ^{1.75}}{30 5 ^{1.75}} = \frac{29 3 ^{1.75}}{80000 \cdot 30 5 ^{1.75}}

= \frac{29 3 ^{1.75}}{80000 \cdot 30 5 ^{1.75}}

\frac{24}{- 20}

y (e^{- 2 y}) d y

10 e^{- x}

(2 - 5 x)^{- 2}

\frac{d ^{2}}{d x ^{2}} ((y^{2}) (x e^{- x}))

What is (2.5*10^{-5})*(1/2)*(293/305)^{1.75} ?
The solution to (2.5*10^{-5})*(1/2)*(293/305)^{1.75} is (293^{1.75})/(80000*305^{1.75)}