What is (320k^5)(316k^7) ?

The solution to (320k^5)(316k^7) is 101120k^{12}

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simplify (320k^5)(316k^7)

simplify

(320 k^{5}) (316 k^{7})

101120 k^{12}

Solution steps

(320 k^{5}) (316 k^{7})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

k^{5} k^{7} = k^{5 + 7}

= 320 \cdot 316 k^{5 + 7}

Add the numbers:

5 + 7 = 12

= 320 \cdot 316 k^{12}

Multiply the numbers:

320 \cdot 316 = 101120

= 101120 k^{12}

(a b^{- 1} + a^{- 1} b) (a^{- 2} + b^{- 2})^{- 1}

e^{- y} e^{y}

0.5 \cdot 1 0^{- 6} (10000)

(e^{x + 7})^{2}

(\frac{( 0.19 = 0.1 )}{0.8})^{- 2}