What are the solutions to the equation x^2-4x=6 ?

The solutions to the equation x^2-4x=6 are x=2+sqrt(10),x=2-sqrt(10)

Find the zeros of x^2-4x=6

The zeros of x^2-4x=6 are x=2+sqrt(10),x=2-sqrt(10)

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x^{2} - 4 x = 6

x = 2 + 10, x = 2 - 10

Solution steps

x^{2} - 4 x = 6

Move

6

to the left side

x^{2} - 4 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 6) = 210

x_{1, 2} = \frac{- ( - 4 ) \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 10}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 10}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 10}{2 \cdot 1} : 2 + 10

x = \frac{- ( - 4 ) - 2 10}{2 \cdot 1} : 2 - 10

The solutions to the quadratic equation are:

x = 2 + 10, x = 2 - 10

x^{3} - 4 x \geq 0

448

x^{2} - 8 x + 7 < 0

- 2 x^{4} + 3 x^{3} - 8 x^{2} + 3 x

3 + 3 x - 1 = x + 2 + 2 x

What are the solutions to the equation x^2-4x=6 ?
The solutions to the equation x^2-4x=6 are x=2+sqrt(10),x=2-sqrt(10)
Find the zeros of x^2-4x=6
The zeros of x^2-4x=6 are x=2+sqrt(10),x=2-sqrt(10)