What is (n^2pi^2(1)^2)sin(npi(1)) ?

The solution to (n^2pi^2(1)^2)sin(npi(1)) is pi^2n^2sin(pin)

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simplify (n^2pi^2(1)^2)sin(npi(1))

simplify

(n^{2} π^{2} (1)^{2}) sin (nπ (1))

π^{2} n^{2} sin (πn)

Solution steps

(n^{2} π^{2} (1)^{2}) sin (nπ (1))

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

π^{2} n^{2} = (πn)^{2}

= 1^{2} sin (1 πn) (πn)^{2}

Apply rule

1^{a} = 1

1^{2} = 1

= 1 \cdot sin (1 πn) (πn)^{2}

(πn)^{2} = π^{2} n^{2}

= 1 \cdot π^{2} n^{2} sin (1 πn)

Refine

= π^{2} n^{2} sin (πn)

e^{- \frac{1}{3 x}}

19000 e^{- 0.07 t \cdot 11}

0.9 (5.7 \cdot 1 0^{- 8}) (285.15)^{4}

A g^{2} C r^{2} O^{7}

What is (n^2pi^2(1)^2)sin(npi(1)) ?
The solution to (n^2pi^2(1)^2)sin(npi(1)) is pi^2n^2sin(pin)