What are the solutions to the equation (z+6)^2=7 ?

The solutions to the equation (z+6)^2=7 are z=sqrt(7)-6,z=-sqrt(7)-6

Find the zeros of (z+6)^2=7

The zeros of (z+6)^2=7 are z=sqrt(7)-6,z=-sqrt(7)-6

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(z + 6)^{2} = 7

z = 7 - 6, z = - 7 - 6

Solution steps

(z + 6)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 6 = 7 : z = 7 - 6

Solve

z + 6 = - 7 : z = - 7 - 6

The solutions to the quadratic equation are:

z = 7 - 6, z = - 7 - 6

- 5 x - 9 \geq - 4

\frac{6}{4} + \frac{2}{4}

- 9 - 3 (- 3) \leq 15

\frac{2 y - 1}{15} = \frac{y}{10}

What are the solutions to the equation (z+6)^2=7 ?
The solutions to the equation (z+6)^2=7 are z=sqrt(7)-6,z=-sqrt(7)-6
Find the zeros of (z+6)^2=7
The zeros of (z+6)^2=7 are z=sqrt(7)-6,z=-sqrt(7)-6