What is e^{-3(t-2)}u(t-2) ?

The solution to e^{-3(t-2)}u(t-2) is (u(t-2))/(e^{3(t-2))}

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simplify e^{-3(t-2)}u(t-2)

simplify

e^{- 3 (t - 2)} u (t - 2)

\frac{u ( t - 2 )}{e ^{3 (t - 2)}}

Solution steps

e^{- 3 (t - 2)} u (t - 2)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{3 (t - 2)}} u (t - 2)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot u ( t - 2 )}{e ^{3 (t - 2)}}

Multiply:

1 \cdot u = u

= \frac{u ( t - 2 )}{e ^{3 (t - 2)}}

c^{6} h^{12} o^{6}

\frac{( \frac{2}{9} ) ^{2}}{( \frac{2}{9} ) _{- 2}}

(8.99 \cdot 1 0^{9}) (1.6 \cdot 1 0^{- 19})

1.76 \cdot 1 0^{- 5}

What is e^{-3(t-2)}u(t-2) ?
The solution to e^{-3(t-2)}u(t-2) is (u(t-2))/(e^{3(t-2))}