What is (x^6+5x^4+3x^2-2x)entre(x^2-x+3) ?

The solution to (x^6+5x^4+3x^2-2x)entre(x^2-x+3) is e^2ntr(x^2-x+3)(x^6+5x^4+3x^2-2x)

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simplify (x^6+5x^4+3x^2-2x)entre(x^2-x+3)

simplify

(x^{6} + 5 x^{4} + 3 x^{2} - 2 x) e n t re (x^{2} - x + 3)

e^{2} n t r (x^{2} - x + 3) (x^{6} + 5 x^{4} + 3 x^{2} - 2 x)

Solution steps

(x^{6} + 5 x^{4} + 3 x^{2} - 2 x) e n t re (x^{2} - x + 3)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ee = e^{1 + 1}

= (x^{6} + 5 x^{4} + 3 x^{2} - 2 x) n t r e^{1 + 1} (x^{2} - x + 3)

Add the numbers:

1 + 1 = 2

= (x^{6} + 5 x^{4} + 3 x^{2} - 2 x) n t r e^{2} (x^{2} - x + 3)

89^{2}

e^{- (0.0005 (2 + 4 \cdot 5000 + 2 \cdot 500 0^{1.5})) 5000}

\frac{2}{28 7 ^{2} \cdot 2} \cdot (1 0^{- 6})

72 x^{10} y^{25} e n t r e^{6} x^{10} y^{25}

a^{2 x + 6}

What is (x^6+5x^4+3x^2-2x)entre(x^2-x+3) ?
The solution to (x^6+5x^4+3x^2-2x)entre(x^2-x+3) is e^2ntr(x^2-x+3)(x^6+5x^4+3x^2-2x)