What is 40*9.8 m/(s^2)*31*10^{-1} ?

The solution to 40*9.8 m/(s^2)*31*10^{-1} is (6076m)/(5s^2)

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simplify 409.8 m/(s^2)31*10^{-1}

simplify

40 \cdot 9.8 \frac{m}{s ^{2}} \cdot 31 \cdot 1 0^{- 1}

\frac{6076 m}{5 s ^{2}}

Solution steps

40 \cdot 9.8 \cdot \frac{m}{s ^{2}} \cdot 31 \cdot 1 0^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

1 0^{- 1} = \frac{1}{10}

= 40 \cdot 9.8 \cdot \frac{m}{s ^{2}} \cdot 31 \cdot \frac{1}{10}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{40 \cdot 9.8 m \cdot 31 \cdot 1}{s ^{2} \cdot 10}

Multiply the numbers:

40 \cdot 9.8 \cdot 31 \cdot 1 = 12152

= \frac{12152 m}{s ^{2} \cdot 10}

Factor the number:

12152 = 2 \cdot 6076

= \frac{2 \cdot 6076 m}{s ^{2} \cdot 10}

Factor the number:

10 = 2 \cdot 5

= \frac{2 \cdot 6076 m}{s ^{2} \cdot 2 \cdot 5}

Cancel the common factor:

2

= \frac{6076 m}{s ^{2} \cdot 5}

= \frac{6076 m}{5 s ^{2}}

(3 m n^{4}) (7 k^{2} m^{3} n^{7})

9.81 x 1 0^{- 4}

17 e^{- \frac{10}{100}}

What is 40*9.8 m/(s^2)*31*10^{-1} ?
The solution to 40*9.8 m/(s^2)*31*10^{-1} is (6076m)/(5s^2)