What are the solutions to the equation 27x^2+12x-8=0 ?

The solutions to the equation 27x^2+12x-8=0 are x=(2(sqrt(7)-1))/9 ,x=-(2(1+sqrt(7)))/9

Find the zeros of 27x^2+12x-8=0

The zeros of 27x^2+12x-8=0 are x=(2(sqrt(7)-1))/9 ,x=-(2(1+sqrt(7)))/9

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27 x^{2} + 12 x - 8 = 0

x = \frac{2 ( 7 - 1 )}{9}, x = - \frac{2 ( 1 + 7 )}{9}

Solution steps

27 x^{2} + 12 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 27 ( - 8 )}{2 \cdot 27}

1 2^{2} - 4 \cdot 27 (- 8) = 127

x_{1, 2} = \frac{- 12 \pm 12 7}{2 \cdot 27}

Separate the solutions

x_{1} = \frac{- 12 + 12 7}{2 \cdot 27}, x_{2} = \frac{- 12 - 12 7}{2 \cdot 27}

x = \frac{- 12 + 12 7}{2 \cdot 27} : \frac{2 ( 7 - 1 )}{9}

x = \frac{- 12 - 12 7}{2 \cdot 27} : - \frac{2 ( 1 + 7 )}{9}

The solutions to the quadratic equation are:

x = \frac{2 ( 7 - 1 )}{9}, x = - \frac{2 ( 1 + 7 )}{9}

- 3 x = - 15

14 x - 7 > 12 x

x^{4} - 11 x^{2} - 80

4 n^{2} - 1

4 > \frac{2 - 3 x}{7} \geq - 2

What are the solutions to the equation 27x^2+12x-8=0 ?
The solutions to the equation 27x^2+12x-8=0 are x=(2(sqrt(7)-1))/9 ,x=-(2(1+sqrt(7)))/9
Find the zeros of 27x^2+12x-8=0
The zeros of 27x^2+12x-8=0 are x=(2(sqrt(7)-1))/9 ,x=-(2(1+sqrt(7)))/9