What are the solutions to the equation 0=-8x^2-10x-5 ?

The solutions to the equation 0=-8x^2-10x-5 are x=-5/8-i(sqrt(15))/8 ,x=-5/8+i(sqrt(15))/8

Find the zeros of 0=-8x^2-10x-5

The zeros of 0=-8x^2-10x-5 are x=-5/8-i(sqrt(15))/8 ,x=-5/8+i(sqrt(15))/8

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0 = - 8 x^{2} - 10 x - 5

x = - \frac{5}{8} - i \frac{15}{8}, x = - \frac{5}{8} + i \frac{15}{8}

Solution steps

0 = - 8 x^{2} - 10 x - 5

Switch sides

- 8 x^{2} - 10 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( - 8 ) ( - 5 )}{2 ( - 8 )}

Simplify

(- 10)^{2} - 4 (- 8) (- 5) : 215 i

x_{1, 2} = \frac{- ( - 10 ) \pm 2 15 i}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 15 i}{2 ( - 8 )}, x_{2} = \frac{- ( - 10 ) - 2 15 i}{2 ( - 8 )}

x = \frac{- ( - 10 ) + 2 15 i}{2 ( - 8 )} : - \frac{5}{8} - i \frac{15}{8}

x = \frac{- ( - 10 ) - 2 15 i}{2 ( - 8 )} : - \frac{5}{8} + i \frac{15}{8}

The solutions to the quadratic equation are:

x = - \frac{5}{8} - i \frac{15}{8}, x = - \frac{5}{8} + i \frac{15}{8}

\frac{3 ^{3}}{2}

7 (x - 5) = 9 x - 3

(2 x - 4)^{2} - 2 x (x - 2) = 48

4 \cdot (3 - x) < x + 12

\frac{3}{4} + 1

What are the solutions to the equation 0=-8x^2-10x-5 ?
The solutions to the equation 0=-8x^2-10x-5 are x=-5/8-i(sqrt(15))/8 ,x=-5/8+i(sqrt(15))/8
Find the zeros of 0=-8x^2-10x-5
The zeros of 0=-8x^2-10x-5 are x=-5/8-i(sqrt(15))/8 ,x=-5/8+i(sqrt(15))/8