What is (h\circ h^{-1})(-1) ?

The solution to (h\circ h^{-1})(-1) is -\circ

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simplify (h\circ h^{-1})(-1)

simplify

(h \circ h^{- 1}) (- 1)

- \circ

Decimal Notation

- 1

Solution steps

(h \circ h^{- 1}) (- 1)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

h h^{- 1} = h^{1 - 1}

= \circ h^{1 - 1} (- 1)

Subtract the numbers:

1 - 1 = 0

= \circ h^{0} (- 1)

Apply rule

a^{0} = 1, a \neq = 0

h^{0} = 1

= 1 \cdot (- 1) \circ

Remove parentheses:

(- a) = - a

= - \circ 1 \cdot 1

Multiply:

\circ 1 \cdot 1 = \circ

= - \circ

6.40993609 e^{- 5}

(3 x + 1)^{2}

f a t or a (x + y)

35 (x)^{5} (y)^{4}