What is (e^{(x-1)})/(e^{(x+1))}dx ?

The solution to (e^{(x-1)})/(e^{(x+1))}dx is (dx)/(e^2)

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simplify (e^{(x-1)})/(e^{(x+1))}dx

simplify

\frac{e ^{(x - 1)}}{e ^{(x + 1)}} d x

\frac{d x}{e ^{2}}

Solution steps

\frac{e ^{(x - 1)}}{e ^{(x + 1)}} d x

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

= e^{x - (x + 1) - 1} d x

Expand

x - 1 - (x + 1) : - 2

= e^{- 2} d x

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

e^{- 2} = \frac{1}{e ^{2}}

= \frac{1}{e ^{2}} d x

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot d x}{e ^{2}}

Multiply:

1 \cdot d x = d x

= \frac{d x}{e ^{2}}

((\frac{2}{16})^{7} \cdot (\frac{16}{2})^{- 5})^{\frac{1}{6}}

2 e^{- 9 (2)}

\frac{12}{400} e^{- \frac{0.01}{0.018}}

e^{- \frac{t}{7}}

2 x (2 x^{3})

What is (e^{(x-1)})/(e^{(x+1))}dx ?
The solution to (e^{(x-1)})/(e^{(x+1))}dx is (dx)/(e^2)