What is log_{10}(a)ritmica(sin(x))^x ?

The solution to log_{10}(a)ritmica(sin(x))^x is ari^2ctmsin^x(x)log_{10}(a)

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simplify log_{10}(a)ritmica(sin(x))^x

simplify

lo g_{10} (a) r i t mi c a (sin (x))^{x}

a r i^{2} c t m sin^{x} (x) lo g_{10} (a)

Solution steps

lo g_{10} (a) r i t mi c a sin^{x} (x)

Apply exponent rule:

aa = a^{2}

ii = i^{2}

= lo g_{10} (a) r i^{2} t m c a sin^{x} (x)

= a r i^{2} c t m sin^{x} (x) lo g_{10} (a)

cos (x)

- a \cdot b \cdot t^{b - 1} \cdot e^{- a \cdot t^{b}}

\frac{9 - x ^{2}}{x ^{2} - 4}

1 - cos (θ) 1 + cos (θ)

- (\infty^{2} + 1) e^{- \infty}

What is log_{10}(a)ritmica(sin(x))^x ?
The solution to log_{10}(a)ritmica(sin(x))^x is ari^2ctmsin^x(x)log_{10}(a)