What is 40000(1+((0.12)/4))^{-(4(3))} ?

The solution to 40000(1+((0.12)/4))^{-(4(3))} is (40000*100^{12})/(103^{12)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 40000(1+((0.12)/4))^{-(4(3))}

simplify

40000 (1 + (\frac{0.12}{4}))^{- (4 (3))}

\frac{40000 \cdot 10 0 ^{12}}{10 3 ^{12}}

Decimal Notation

28055.19520 \dots

Solution steps

40000 (1 + (\frac{0.12}{4}))^{- (4 (3))}

(1 + (\frac{0.12}{4}))^{- (4 (3))} = (1 + \frac{0.12}{4})^{- 4 \cdot 3}

= 40000 (1 + \frac{0.12}{4})^{- 4 \cdot 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(1 + \frac{0.12}{4})^{- 4 \cdot 3} = \frac{1}{( 1 + \frac{0.12}{4} ) ^{4 \cdot 3}}

= 40000 \cdot \frac{1}{( 1 + \frac{0.12}{4} ) ^{4 \cdot 3}}

(1 + \frac{0.12}{4})^{4 \cdot 3} = \frac{10 3 ^{12}}{10 0 ^{12}}

= 40000 \cdot \frac{1}{\frac{10 3 ^{12}}{10 0 ^{12}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= 40000 \cdot \frac{10 0 ^{12}}{10 3 ^{12}}

40000 \cdot \frac{10 0 ^{12}}{10 3 ^{12}} = \frac{40000 \cdot 10 0 ^{12}}{10 3 ^{12}}

= \frac{40000 \cdot 10 0 ^{12}}{10 3 ^{12}}

v + u v - u

(4 x^{3} y^{5} z) (6 x^{3} y^{5} z)

510 e^{- 0.65 (4)}

2.3886 \cdot 1 0^{- 4} (4.227 \cdot (\frac{x + 460}{1.8}))

3 x (x - 9)^{2} (x - 3)^{2}

What is 40000(1+((0.12)/4))^{-(4(3))} ?
The solution to 40000(1+((0.12)/4))^{-(4(3))} is (40000*100^{12})/(103^{12)}