What is the answer to (4x+2)/3+(2x-1)/5 =2 ?

The answer to (4x+2)/3+(2x-1)/5 =2 is x= 23/26

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(4x+2)/3+(2x-1)/5 =2

\frac{4 x + 2}{3} + \frac{2 x - 1}{5} = 2

x = \frac{23}{26}

Decimal Notation

x = 0.88461 \dots

Solution steps

\frac{4 x + 2}{3} + \frac{2 x - 1}{5} = 2

Multiply by LCM

5 (4 x + 2) + 3 (2 x - 1) = 30

Expand

5 (4 x + 2) + 3 (2 x - 1) : 26 x + 7

26 x + 7 = 30

Move

7

to the right side

26 x = 23

Divide both sides by

26

x = \frac{23}{26}

4 x^{2} - 3 x - 27

3 x^{2} - 10 x y + 8 y^{2}

\frac{1}{4} \cdot 10

11 z^{3} + 110 z^{2} + 99 z

4 t^{2} = 20 t + 150

What is the answer to (4x+2)/3+(2x-1)/5 =2 ?
The answer to (4x+2)/3+(2x-1)/5 =2 is x= 23/26
Solve for x: (4x+2)/3+(2x-1)/5 =2
The solution is x= 23/26