What is e^{-1/4 ln|1-x^2|} ?

The solution to e^{-1/4 ln|1-x^2|} is 1/(\sqrt[4]{|-x^2+1|)}

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simplify e^{-1/4 ln|1-x^2|}

simplify

e^{- \frac{1}{4} l n ∣ 1 - x^{2} ∣}

Solution steps

e^{- \frac{1}{4} l n ∣ 1 - x^{2} ∣}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{\frac{1}{4} l n ∣ - x^{2} + 1 ∣}}

(5 x y^{3}) (7 x^{2} y)

0.5 (\frac{20}{2 ^{21}}) \cdot (1 0^{- 6})

e^{- 2.31}

(a^{2})^{9^{^{'}}}

3 x^{2} (x^{3} + 1)^{2}

What is e^{-1/4 ln|1-x^2|} ?
The solution to e^{-1/4 ln|1-x^2|} is 1/(\sqrt[4]{|-x^2+1|)}