What is (\sqrt[3]{6n})^{4^'} ?

The solution to (\sqrt[3]{6n})^{4^'} is 6^{(4^')/3}n^{(4^')/3}

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simplify (\sqrt[3]{6n})^{4^'}

simplify

6^{\frac{4 ^{'}}{3}} n^{\frac{4 ^{'}}{3}}

Solution steps

Apply radical rule:

= ((6 n)^{\frac{1}{3}})^{4^{^{^{'}}}}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= (6 n)^{\frac{1}{3} \cdot 4^{^{^{'}}}}

Simplify

\frac{1}{3} \cdot 4^{^{'}} : \frac{4 ^{^{'}}}{3}

= (6 n)^{\frac{4 ^{^{'}}}{3}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= 6^{\frac{4 ^{^{^{'}}}}{3}} n^{\frac{4 ^{^{^{'}}}}{3}}

70 0^{2} \cdot 2.636 \cdot 1 0^{- 4}

20 x^{2} y^{2}

24 m^{2} n^{2}

(csc (x))^{- 1}

What is (\sqrt[3]{6n})^{4^'} ?
The solution to (\sqrt[3]{6n})^{4^'} is 6^{(4^')/3}n^{(4^')/3}