What is e^{-ln((abc-c^2b^2v)/(abc))} ?

The solution to e^{-ln((abc-c^2b^2v)/(abc))} is a/(-bcv+a)

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simplify e^{-ln((abc-c^2b^2v)/(abc))}

simplify

e^{- l n (\frac{ab c - c ^{2} b ^{2} v}{ab c})}

\frac{a}{- b c v + a}

Solution steps

e^{- l n (\frac{ab c - c ^{2} b ^{2} v}{ab c})}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{l n (\frac{ab c - c ^{2} b ^{2} v}{ab c})}}

e^{l n (\frac{ab c - c ^{2} b ^{2} v}{ab c})} = \frac{a - b c v}{a}

= \frac{1}{\frac{a - b c v}{a}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{a}{a - b c v}

e^{- \frac{16}{35} t} e^{- \frac{109}{70} t}

e^{- x} cosh (x)

(1 - 3) (1 - 3)

e^{- X} X

What is e^{-ln((abc-c^2b^2v)/(abc))} ?
The solution to e^{-ln((abc-c^2b^2v)/(abc))} is a/(-bcv+a)