What is h*2(0.5h)(4+0.5*4h^2) ?

The solution to h*2(0.5h)(4+0.5*4h^2) is h^2(4+2h^2)

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simplify h2(0.5h)(4+0.54h^2)

simplify

h \cdot 2 (0.5 h) (4 + 0.5 \cdot 4 h^{2})

h^{2} (4 + 2 h^{2})

Solution steps

h \cdot 2 (0.5 h) (4 + 0.5 \cdot 4 h^{2})

Multiply the numbers:

0.5 \cdot 4 = 2

= h \cdot 2 \cdot 0.5 h (4 + 2 h^{2})

Multiply the numbers:

2 \cdot 0.5 = 1

= h \cdot 1 \cdot h (4 + 2 h^{2})

Apply rule:

a \cdot 1 = a

= hh (4 + 2 h^{2})

Apply exponent rule:

aa = a^{2}

hh = h^{2}

= h^{2} (4 + 2 h^{2})

1.2 e^{- 1}

2 (\frac{11}{126} + \frac{2}{18} - \frac{1}{81}) (\frac{5}{14} + 1)^{- 1}

(2 x^{2} y^{2}) (5 x y^{3})

(10 y) (2 y^{3})

What is h*2(0.5h)(4+0.5*4h^2) ?
The solution to h*2(0.5h)(4+0.5*4h^2) is h^2(4+2h^2)