What is ((((16^{1/3})^{-6}))^{(-1)/4})^{1/2} ?

The solution to ((((16^{1/3})^{-6}))^{(-1)/4})^{1/2} is 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((((16^{1/3})^{-6}))^{(-1)/4})^{1/2}

simplify

((((1 6^{\frac{1}{3}})^{- 6}))^{\frac{- 1}{4}})^{\frac{1}{2}}

2

Solution steps

((((1 6^{\frac{1}{3}})^{- 6}))^{\frac{- 1}{4}})^{\frac{1}{2}}

(1 6^{\frac{1}{3}})^{- 6} : 1 6^{- 2}

= ((1 6^{- 2})^{\frac{- 1}{4}})^{\frac{1}{2}}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= (1 6^{- 2})^{\frac{- 1}{4} \cdot \frac{1}{2}}

\frac{- 1}{4} \cdot \frac{1}{2} = - \frac{1}{8}

= (1 6^{- 2})^{- \frac{1}{8}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{( 1 6 ^{- 2} ) ^{\frac{1}{8}}}

(1 6^{- 2})^{\frac{1}{8}} : 1 6^{- \frac{1}{4}}

= \frac{1}{1 6 ^{- \frac{1}{4}}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 6^{- \frac{1}{4}} = \frac{1}{1 6 ^{\frac{1}{4}}}

= \frac{1}{\frac{1}{1 6 ^{\frac{1}{4}}}}

1 6^{\frac{1}{4}} = 2

= \frac{1}{\frac{1}{2}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{2}{1}

Apply the fraction rule:

\frac{a}{1} = a

= 2

(6.6262 \cdot 1 0^{- 34}) (4.01 \cdot 1 0^{14})

4.22 \cdot e^{- t} cos (3)

(18)^{3}

e^{- 1.1}

2 λ e^{- λ t} (- e^{- λ t} + 1) (2 λ e^{- 2 λ t})

What is ((((16^{1/3})^{-6}))^{(-1)/4})^{1/2} ?
The solution to ((((16^{1/3})^{-6}))^{(-1)/4})^{1/2} is 2