What is (4a^{3n-1})(0.5a^{2n+2}) ?

The solution to (4a^{3n-1})(0.5a^{2n+2}) is 2a^{5n+1}

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simplify (4a^{3n-1})(0.5a^{2n+2})

simplify

(4 a^{3 n - 1}) (0.5 a^{2 n + 2})

2 a^{5 n + 1}

Solution steps

(4 a^{3 n - 1}) (0.5 a^{2 n + 2})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

a^{3 n - 1} a^{2 n + 2} = a^{3 n - 1 + 2 n + 2}

= 4 \cdot 0.5 a^{3 n - 1 + 2 n + 2}

Simplify

3 n - 1 + 2 n + 2 : 5 n + 1

= 4 \cdot 0.5 a^{5 n + 1}

Multiply the numbers:

4 \cdot 0.5 = 2

= 2 a^{5 n + 1}

(10 t^{4} v^{5}) (3 t^{2} v^{5})

\frac{7 + 5}{7 - 5}

t^{\frac{2}{3}} x^{\frac{2}{3}} (5 t^{2})

(1.412 \cdot 1 0^{- 26}) \cdot (5.024 \cdot 1 0^{22})

(3 y) (15 y^{5})

What is (4a^{3n-1})(0.5a^{2n+2}) ?
The solution to (4a^{3n-1})(0.5a^{2n+2}) is 2a^{5n+1}