What is (r^2sin^2(θ))(2r^2sin(θ)) ?

The solution to (r^2sin^2(θ))(2r^2sin(θ)) is 2r^4sin^3(θ)

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simplify (r^2sin^2(θ))(2r^2sin(θ))

simplify

(r^{2} sin^{2} (θ)) (2 r^{2} sin (θ))

2 r^{4} sin^{3} (θ)

Solution steps

(r^{2} sin^{2} (θ)) (2 r^{2} sin (θ))

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

r^{2} r^{2} = r^{2 + 2}

= sin^{2} (θ) \cdot 2 r^{2 + 2} sin (θ)

Add the numbers:

2 + 2 = 4

= sin^{2} (θ) \cdot 2 r^{4} sin (θ)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

sin^{2} (θ) sin (θ) = sin^{2 + 1} (θ)

= 2 r^{4} sin^{2 + 1} (θ)

Add the numbers:

2 + 1 = 3

= 2 r^{4} sin^{3} (θ)

(y^{2} - 4) (y^{2} - 4)

500 e^{- 1}

2.57 5^{2} \cdot \frac{3 4 ^{2}}{4 ^{2}}

What is (r^2sin^2(θ))(2r^2sin(θ)) ?
The solution to (r^2sin^2(θ))(2r^2sin(θ)) is 2r^4sin^3(θ)