What is expand (2-x)(1-3x)^{-1/2} ?

The solution to expand (2-x)(1-3x)^{-1/2} is (2-x)/((1-3x)^{1/2)}

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expand (2-x)(1-3x)^{-1/2}

expand

(2 - x) (1 - 3 x)^{- \frac{1}{2}}

\frac{2 - x}{( 1 - 3 x ) ^{\frac{1}{2}}}

Solution steps

(2 - x) (1 - 3 x)^{- \frac{1}{2}}

= (1 - 3 x)^{- \frac{1}{2}} (2 - x)

Apply the distributive law:

a (b - c) = ab - a c

(1 - 3 x)^{- \frac{1}{2}} (2 - x) = (1 - 3 x)^{- \frac{1}{2}} \cdot 2 - (1 - 3 x)^{- \frac{1}{2}} x

= (1 - 3 x)^{- \frac{1}{2}} \cdot 2 - (1 - 3 x)^{- \frac{1}{2}} x

Simplify

(1 - 3 x)^{- \frac{1}{2}} \cdot 2 - (1 - 3 x)^{- \frac{1}{2}} x : \frac{2 - x}{( 1 - 3 x ) ^{\frac{1}{2}}}

= \frac{2 - x}{( 1 - 3 x ) ^{\frac{1}{2}}}

- 6 e^{- 2 x}

0.25 \cdot 17.3 \cdot 1 0^{- 6} \cdot 190

[(\frac{5}{2})^{3}]^{- 4} \cdot (\frac{4}{5})^{- 2}

\frac{1}{3} e^{- 30}

4 π (8.85 (10)^{- 12}) (34)^{2} (\frac{1}{100})^{2}

What is expand (2-x)(1-3x)^{-1/2} ?
The solution to expand (2-x)(1-3x)^{-1/2} is (2-x)/((1-3x)^{1/2)}