What is expand \sqrt[n]{6(1+1/n)^{n^2}} ?

The solution to expand \sqrt[n]{6(1+1/n)^{n^2}} is \sqrt[n]{6}\sqrt[n]{(1/n+1)^{n^2}}

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expand \sqrt[n]{6(1+1/n)^{n^2}}

expand

n 6 (1 + \frac{1}{n})^{n^{2}}

n 6 n (\frac{1}{n} + 1)^{n^{2}}

Solution steps

n 6 (1 + \frac{1}{n})^{n^{2}}

Apply radical rule:

n ab = n a n b

n 6 (1 + \frac{1}{n})^{n^{2}} = n 6 n (1 + \frac{1}{n})^{n^{2}}

= n 6 n (\frac{1}{n} + 1)^{n^{2}}

2 x \times e^{- x}

9.01218 \cdot 1.68 \cdot 1 0^{- 26}

x^{- 200 x} d x

5.6 \cdot 1 0^{- 7}

5.6 \cdot 1 0^{- 6}

What is expand \sqrt[n]{6(1+1/n)^{n^2}} ?
The solution to expand \sqrt[n]{6(1+1/n)^{n^2}} is \sqrt[n]{6}\sqrt[n]{(1/n+1)^{n^2}}