What is (sqrt((-60^2)+40^2+(-80^2)))^2 ?

The solution to (sqrt((-60^2)+40^2+(-80^2)))^2 is -8400

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (sqrt((-60^2)+40^2+(-80^2)))^2

simplify

((- 6 0^{2}) + 4 0^{2} + (- 8 0^{2}))^{2}

- 8400

Solution steps

((- 6 0^{2}) + 4 0^{2} + (- 8 0^{2}))^{2}

(- 6 0^{2}) + 4 0^{2} + (- 8 0^{2}) = - 6 0^{2} + 4 0^{2} - 8 0^{2}

= (- 6 0^{2} + 4 0^{2} - 8 0^{2})^{2}

- 6 0^{2} + 4 0^{2} - 8 0^{2} = 2021 i

= (2021 i)^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(2021 i)^{2} = 2 0^{2} (21)^{2} i^{2}

= 2 0^{2} (21)^{2} i^{2}

2 0^{2} = 400

= 400 (21)^{2} i^{2}

(21)^{2} = 21

= 400 \cdot 21 i^{2}

Multiply the numbers:

400 \cdot 21 = 8400

= 8400 i^{2}

Apply imaginary number rule:

i^{2} = - 1

= 8400 (- 1)

Multiply the numbers:

8400 (- 1) = - 8400

= - 8400

e^{- 5} \frac{5 ^{0}}{0 !}

(x - 2)^{2} (x + 5)^{2}

(sin (x)) e^{- x}

(sin (x))^{2} (cos (x))^{2}

What is (sqrt((-60^2)+40^2+(-80^2)))^2 ?
The solution to (sqrt((-60^2)+40^2+(-80^2)))^2 is -8400