What is 1/2 (x+1)^{-0.5} ?

The solution to 1/2 (x+1)^{-0.5} is 1/(2(x+1)^{0.5)}

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simplify 1/2 (x+1)^{-0.5}

simplify

\frac{1}{2} (x + 1)^{- 0.5}

\frac{1}{2 ( x + 1 ) ^{0.5}}

Solution steps

\frac{1}{2} (x + 1)^{- 0.5}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(x + 1)^{- 0.5} = \frac{1}{( x + 1 ) ^{0.5}}

= \frac{1}{2} \cdot \frac{1}{( x + 1 ) ^{0.5}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 1}{2 ( x + 1 ) ^{0.5}}

Multiply the numbers:

1 \cdot 1 = 1

= \frac{1}{2 ( x + 1 ) ^{0.5}}

0.237 I (x^{1}) (x^{3} x^{5}) d x

t^{41.6} \cdot e^{- 0.92 t}

18 e^{t} \cdot 18 e^{t}

e^{- 4 x}

e^{5} e^{1}