What is sqrt(2^x),^{2^{2x-1}},^{4^{3x-2}} ?

The solution to sqrt(2^x),^{2^{2x-1}},^{4^{3x-2}} is sqrt(2^x),^{2^{2x-1}+4^{3x-2}}

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simplify sqrt(2^x),^{2^{2x-1}},^{4^{3x-2}}

simplify

2^{x},^{2^{2 x - 1} + 4^{3 x - 2}}

Solution steps

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2 + 2 2

\frac{2}{3}

(5 ab) (a b^{2})

(\frac{x - 1}{x + 1}) (x + 1)^{2}

What is sqrt(2^x),^{2^{2x-1}},^{4^{3x-2}} ?
The solution to sqrt(2^x),^{2^{2x-1}},^{4^{3x-2}} is sqrt(2^x),^{2^{2x-1}+4^{3x-2}}