What is expand 2sqrt(x/(x+1))*(x+1)^2 ?

The solution to expand 2sqrt(x/(x+1))*(x+1)^2 is 2sqrt(x/(x+1))x^2+4xsqrt(x/(x+1))+2sqrt(x/(x+1))

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expand 2sqrt(x/(x+1))*(x+1)^2

expand

2 \frac{x}{x + 1} \cdot (x + 1)^{2}

2 \frac{x}{x + 1} x^{2} + 4 x \frac{x}{x + 1} + 2 \frac{x}{x + 1}

Solution steps

2 \frac{x}{x + 1} (x + 1)^{2}

Expand

(x + 1)^{2} : x^{2} + 2 x + 1

= 2 \frac{x}{x + 1} (x^{2} + 2 x + 1)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

2 \frac{x}{x + 1} (x^{2} + 2 x + 1) = 2 \frac{x}{x + 1} x^{2} + 2 \frac{x}{x + 1} \cdot 2 x + 2 \frac{x}{x + 1} \cdot 1

= 2 \frac{x}{x + 1} x^{2} + 2 \frac{x}{x + 1} \cdot 2 x + 2 \frac{x}{x + 1} \cdot 1

2 \frac{x}{x + 1} \cdot 2 x = 4 x \frac{x}{x + 1}

2 \frac{x}{x + 1} \cdot 1 = 2 \frac{x}{x + 1}

= 2 \frac{x}{x + 1} x^{2} + 4 x \frac{x}{x + 1} + 2 \frac{x}{x + 1}

2 (2.31 \cdot 1 0^{- 19} [\frac{( + 1 ) ( - 1 )}{0.8}])

4^{n} (- \frac{1}{4})^{n}

(2 x^{4} y^{2} z^{5}) (2 x^{5} y^{3} z^{4})

(x - 3) (x - 1)^{2} (x + 2)^{2}

What is expand 2sqrt(x/(x+1))*(x+1)^2 ?
The solution to expand 2sqrt(x/(x+1))*(x+1)^2 is 2sqrt(x/(x+1))x^2+4xsqrt(x/(x+1))+2sqrt(x/(x+1))