What are the solutions to the equation x^2-14x=-29 ?

The solutions to the equation x^2-14x=-29 are x=7+2sqrt(5),x=7-2sqrt(5)

Find the zeros of x^2-14x=-29

The zeros of x^2-14x=-29 are x=7+2sqrt(5),x=7-2sqrt(5)

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x^{2} - 14 x = - 29

x = 7 + 25, x = 7 - 25

Solution steps

x^{2} - 14 x = - 29

Move

29

to the left side

x^{2} - 14 x + 29 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 29}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 29 = 45

x_{1, 2} = \frac{- ( - 14 ) \pm 4 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 4 5}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 4 5}{2 \cdot 1}

x = \frac{- ( - 14 ) + 4 5}{2 \cdot 1} : 7 + 25

x = \frac{- ( - 14 ) - 4 5}{2 \cdot 1} : 7 - 25

The solutions to the quadratic equation are:

x = 7 + 25, x = 7 - 25

(u - 14) (u + 10) = - 104

\frac{1}{2} - \frac{3}{2} i

\frac{b}{30} = \frac{4}{5}

x + 5.5 + 8 = 5 x - 13.5 - 4 x

a x + b x - a y - b y

What are the solutions to the equation x^2-14x=-29 ?
The solutions to the equation x^2-14x=-29 are x=7+2sqrt(5),x=7-2sqrt(5)
Find the zeros of x^2-14x=-29
The zeros of x^2-14x=-29 are x=7+2sqrt(5),x=7-2sqrt(5)