What is (-4mnp)left(-6m^2n^3p)left(5m^4n^2p^2) ?

The solution to (-4mnp)left(-6m^2n^3p)left(5m^4n^2p^2) is 120e^2l^2m^7n^6p^4f^2t^2

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simplify (-4mnp)left(-6m^2n^3p)left(5m^4n^2p^2)

simplify

(- 4 mn p) l e f t (- 6 m^{2} n^{3} p) l e f t (5 m^{4} n^{2} p^{2})

120 e^{2} l^{2} m^{7} n^{6} p^{4} f^{2} t^{2}

Solution steps

(- 4 mn p) l e f t (- 6 m^{2} n^{3} p) l e f t (5 m^{4} n^{2} p^{2})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ll = l^{1 + 1}

= (- 4 mn p) e f t (- 6 m^{2} n^{3} p) l^{1 + 1} e f t \cdot 5 m^{4} n^{2} p^{2}

Add the numbers:

1 + 1 = 2

= (- 4 mn p) e f t (- 6 m^{2} n^{3} p) l^{2} e f t \cdot 5 m^{4} n^{2} p^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ee = e^{1 + 1}

= (- 4 mn p) f t (- 6 m^{2} n^{3} p) l^{2} e^{1 + 1} f t \cdot 5 m^{4} n^{2} p^{2}

Add the numbers:

1 + 1 = 2

= (- 4 mn p) f t (- 6 m^{2} n^{3} p) l^{2} e^{2} f t \cdot 5 m^{4} n^{2} p^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ff = f^{1 + 1}

= (- 4 mn p) t (- 6 m^{2} n^{3} p) l^{2} e^{2} f^{1 + 1} t \cdot 5 m^{4} n^{2} p^{2}

Add the numbers:

1 + 1 = 2

= (- 4 mn p) t (- 6 m^{2} n^{3} p) l^{2} e^{2} f^{2} t \cdot 5 m^{4} n^{2} p^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

tt = t^{1 + 1}

= (- 4 mn p) (- 6 m^{2} n^{3} p) l^{2} e^{2} f^{2} t^{1 + 1} \cdot 5 m^{4} n^{2} p^{2}

Add the numbers:

1 + 1 = 2

= (- 4 mn p) (- 6 m^{2} n^{3} p) l^{2} e^{2} f^{2} t^{2} \cdot 5 m^{4} n^{2} p^{2}

Remove parentheses:

(- a) = - a, - (- a) = a

= 4 mn p \cdot 6 m^{2} n^{3} p l^{2} e^{2} f^{2} t^{2} \cdot 5 m^{4} n^{2} p^{2}

Multiply the numbers:

4 \cdot 6 \cdot 5 = 120

= 120 e^{2} l^{2} m^{4} m^{2} m n^{3} n^{2} n p^{2} pp f^{2} t^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

m m^{2} m^{4} = m^{1 + 2 + 4}

= 120 n p n^{3} p l^{2} e^{2} f^{2} t^{2} m^{1 + 2 + 4} n^{2} p^{2}

Add the numbers:

1 + 2 + 4 = 7

= 120 n p n^{3} p l^{2} e^{2} f^{2} t^{2} m^{7} n^{2} p^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

n n^{3} n^{2} = n^{1 + 3 + 2}

= 120 pp l^{2} e^{2} f^{2} t^{2} m^{7} n^{1 + 3 + 2} p^{2}

Add the numbers:

1 + 3 + 2 = 6

= 120 pp l^{2} e^{2} f^{2} t^{2} m^{7} n^{6} p^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

pp p^{2} = p^{1 + 1 + 2}

= 120 l^{2} e^{2} f^{2} t^{2} m^{7} n^{6} p^{1 + 1 + 2}

Add the numbers:

1 + 1 + 2 = 4

= 120 l^{2} e^{2} f^{2} t^{2} m^{7} n^{6} p^{4}

(2 t \cdot e^{2 t}) \cdot e^{- t}

(5 a b^{6}) (8 b^{10})

(8^{l o g_{8} (π)})^{2.4}

e^{- 4 x} \cdot 4

What is (-4mnp)left(-6m^2n^3p)left(5m^4n^2p^2) ?
The solution to (-4mnp)left(-6m^2n^3p)left(5m^4n^2p^2) is 120e^2l^2m^7n^6p^4f^2t^2