What is P^1(-3,-8)P^2(-6,-4) ?

The solution to P^1(-3,-8)P^2(-6,-4) is (-3,-8)(-6,-4)P^3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify P^1(-3,-8)P^2(-6,-4)

simplify

P^{1} (- 3, - 8) P^{2} (- 6, - 4)

(- 3, - 8) (- 6, - 4) P^{3}

Solution steps

P^{1} (- 3, - 8) P^{2} (- 6, - 4)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

P^{1} P^{2} = P^{1 + 2}

= (- 3, - 8) P^{1 + 2} (- 6, - 4)

Add the numbers:

1 + 2 = 3

= (- 3, - 8) P^{3} (- 6, - 4)

3.1972 x 1 0^{- 11} \cdot 115

(\frac{1}{81})^{x - 2} (27)^{x}

- 5 x + 2^{2}

(2 k + 2)^{2} (k + 2)^{2}

\frac{5 π}{36} c x^{3200} c a l x \frac{2 π}{3} c

What is P^1(-3,-8)P^2(-6,-4) ?
The solution to P^1(-3,-8)P^2(-6,-4) is (-3,-8)(-6,-4)P^3