What are the solutions to the equation 36x^2+49=0 ?

The solutions to the equation 36x^2+49=0 are x= 7/6 i,x=-7/6 i

Find the zeros of 36x^2+49=0

The zeros of 36x^2+49=0 are x= 7/6 i,x=-7/6 i

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36 x^{2} + 49 = 0

x = \frac{7}{6} i, x = - \frac{7}{6} i

Solution steps

36 x^{2} + 49 = 0

Move

49

to the right side

36 x^{2} = - 49

Divide both sides by

36

x^{2} = - \frac{49}{36}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{49}{36}, x = - - \frac{49}{36}

- \frac{49}{36} = \frac{7}{6} i

- - \frac{49}{36} = - \frac{7}{6} i

x = \frac{7}{6} i, x = - \frac{7}{6} i

- 46 - 6

(- 27) \frac{1}{3}

2 (x - 4)^{2} = 50

(2 x)^{\frac{3}{2}}

- \frac{7}{- 2}

What are the solutions to the equation 36x^2+49=0 ?
The solutions to the equation 36x^2+49=0 are x= 7/6 i,x=-7/6 i
Find the zeros of 36x^2+49=0
The zeros of 36x^2+49=0 are x= 7/6 i,x=-7/6 i